Integrand size = 35, antiderivative size = 61 \[ \int \frac {\sec (e+f x) \sqrt {a+a \sec (e+f x)}}{\sqrt {c+d \sec (e+f x)}} \, dx=\frac {2 \sqrt {a} \text {arctanh}\left (\frac {\sqrt {a} \sqrt {d} \tan (e+f x)}{\sqrt {a+a \sec (e+f x)} \sqrt {c+d \sec (e+f x)}}\right )}{\sqrt {d} f} \]
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Time = 0.17 (sec) , antiderivative size = 61, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.057, Rules used = {4065, 212} \[ \int \frac {\sec (e+f x) \sqrt {a+a \sec (e+f x)}}{\sqrt {c+d \sec (e+f x)}} \, dx=\frac {2 \sqrt {a} \text {arctanh}\left (\frac {\sqrt {a} \sqrt {d} \tan (e+f x)}{\sqrt {a \sec (e+f x)+a} \sqrt {c+d \sec (e+f x)}}\right )}{\sqrt {d} f} \]
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Rule 212
Rule 4065
Rubi steps \begin{align*} \text {integral}& = -\frac {(2 a) \text {Subst}\left (\int \frac {1}{1-a d x^2} \, dx,x,-\frac {\tan (e+f x)}{\sqrt {a+a \sec (e+f x)} \sqrt {c+d \sec (e+f x)}}\right )}{f} \\ & = \frac {2 \sqrt {a} \text {arctanh}\left (\frac {\sqrt {a} \sqrt {d} \tan (e+f x)}{\sqrt {a+a \sec (e+f x)} \sqrt {c+d \sec (e+f x)}}\right )}{\sqrt {d} f} \\ \end{align*}
Time = 0.72 (sec) , antiderivative size = 102, normalized size of antiderivative = 1.67 \[ \int \frac {\sec (e+f x) \sqrt {a+a \sec (e+f x)}}{\sqrt {c+d \sec (e+f x)}} \, dx=\frac {\sqrt {2} \text {arctanh}\left (\frac {\sqrt {2} \sqrt {d} \sin \left (\frac {1}{2} (e+f x)\right )}{\sqrt {d+c \cos (e+f x)}}\right ) \sqrt {d+c \cos (e+f x)} \sec \left (\frac {1}{2} (e+f x)\right ) \sqrt {a (1+\sec (e+f x))}}{\sqrt {d} f \sqrt {c+d \sec (e+f x)}} \]
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Leaf count of result is larger than twice the leaf count of optimal. \(277\) vs. \(2(49)=98\).
Time = 5.51 (sec) , antiderivative size = 278, normalized size of antiderivative = 4.56
method | result | size |
default | \(\frac {\sqrt {2}\, \sqrt {a \left (\sec \left (f x +e \right )+1\right )}\, \sqrt {c +d \sec \left (f x +e \right )}\, \left (\ln \left (\frac {2 \sqrt {2}\, \sqrt {-d}\, \sqrt {-\frac {2 \left (d +c \cos \left (f x +e \right )\right )}{\cos \left (f x +e \right )+1}}\, \sin \left (f x +e \right )-2 \sin \left (f x +e \right ) c -2 \sin \left (f x +e \right ) d +2 c \cos \left (f x +e \right )-2 d \cos \left (f x +e \right )-2 c +2 d}{-\cos \left (f x +e \right )+1+\sin \left (f x +e \right )}\right )-\ln \left (-\frac {2 \left (\sqrt {2}\, \sqrt {-d}\, \sqrt {-\frac {2 \left (d +c \cos \left (f x +e \right )\right )}{\cos \left (f x +e \right )+1}}\, \sin \left (f x +e \right )-\sin \left (f x +e \right ) c -\sin \left (f x +e \right ) d -c \cos \left (f x +e \right )+d \cos \left (f x +e \right )+c -d \right )}{\cos \left (f x +e \right )-1+\sin \left (f x +e \right )}\right )\right ) \cos \left (f x +e \right )}{f \sqrt {-d}\, \left (\cos \left (f x +e \right )+1\right ) \sqrt {-\frac {2 \left (d +c \cos \left (f x +e \right )\right )}{\cos \left (f x +e \right )+1}}}\) | \(278\) |
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Leaf count of result is larger than twice the leaf count of optimal. 116 vs. \(2 (49) = 98\).
Time = 0.41 (sec) , antiderivative size = 307, normalized size of antiderivative = 5.03 \[ \int \frac {\sec (e+f x) \sqrt {a+a \sec (e+f x)}}{\sqrt {c+d \sec (e+f x)}} \, dx=\left [\frac {\sqrt {\frac {a}{d}} \log \left (-\frac {8 \, a c d \cos \left (f x + e\right ) + {\left (a c^{2} - 6 \, a c d + a d^{2}\right )} \cos \left (f x + e\right )^{3} + 4 \, {\left (2 \, d^{2} \cos \left (f x + e\right ) + {\left (c d - d^{2}\right )} \cos \left (f x + e\right )^{2}\right )} \sqrt {\frac {a}{d}} \sqrt {\frac {a \cos \left (f x + e\right ) + a}{\cos \left (f x + e\right )}} \sqrt {\frac {c \cos \left (f x + e\right ) + d}{\cos \left (f x + e\right )}} \sin \left (f x + e\right ) + 8 \, a d^{2} + {\left (a c^{2} + 2 \, a c d - 7 \, a d^{2}\right )} \cos \left (f x + e\right )^{2}}{\cos \left (f x + e\right )^{3} + \cos \left (f x + e\right )^{2}}\right )}{2 \, f}, \frac {\sqrt {-\frac {a}{d}} \arctan \left (-\frac {2 \, d \sqrt {-\frac {a}{d}} \sqrt {\frac {a \cos \left (f x + e\right ) + a}{\cos \left (f x + e\right )}} \sqrt {\frac {c \cos \left (f x + e\right ) + d}{\cos \left (f x + e\right )}} \cos \left (f x + e\right ) \sin \left (f x + e\right )}{{\left (a c - a d\right )} \cos \left (f x + e\right )^{2} + 2 \, a d + {\left (a c + a d\right )} \cos \left (f x + e\right )}\right )}{f}\right ] \]
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\[ \int \frac {\sec (e+f x) \sqrt {a+a \sec (e+f x)}}{\sqrt {c+d \sec (e+f x)}} \, dx=\int \frac {\sqrt {a \left (\sec {\left (e + f x \right )} + 1\right )} \sec {\left (e + f x \right )}}{\sqrt {c + d \sec {\left (e + f x \right )}}}\, dx \]
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\[ \int \frac {\sec (e+f x) \sqrt {a+a \sec (e+f x)}}{\sqrt {c+d \sec (e+f x)}} \, dx=\int { \frac {\sqrt {a \sec \left (f x + e\right ) + a} \sec \left (f x + e\right )}{\sqrt {d \sec \left (f x + e\right ) + c}} \,d x } \]
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\[ \int \frac {\sec (e+f x) \sqrt {a+a \sec (e+f x)}}{\sqrt {c+d \sec (e+f x)}} \, dx=\int { \frac {\sqrt {a \sec \left (f x + e\right ) + a} \sec \left (f x + e\right )}{\sqrt {d \sec \left (f x + e\right ) + c}} \,d x } \]
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Timed out. \[ \int \frac {\sec (e+f x) \sqrt {a+a \sec (e+f x)}}{\sqrt {c+d \sec (e+f x)}} \, dx=\int \frac {\sqrt {a+\frac {a}{\cos \left (e+f\,x\right )}}}{\cos \left (e+f\,x\right )\,\sqrt {c+\frac {d}{\cos \left (e+f\,x\right )}}} \,d x \]
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